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4x-9x^2-15x+3=0
We add all the numbers together, and all the variables
-9x^2-11x+3=0
a = -9; b = -11; c = +3;
Δ = b2-4ac
Δ = -112-4·(-9)·3
Δ = 229
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{229}}{2*-9}=\frac{11-\sqrt{229}}{-18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{229}}{2*-9}=\frac{11+\sqrt{229}}{-18} $
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